Summary: Perturbation theory is the most widely used approximate method. “Time-independent perturbation theory” deals with bound states eg the spectrum of the real hydrogen atom and its response to extermal fields.
Perturbation theory is applicable when the Hamiltonian can be split into two parts, with the first part being exactly solvable and the second part being small in comparison. The first part is always written , and we will denote its eigenstates by and energies by (with wave functions ). These we know. The eigenstates and energies of the full Hamiltonian are denoted and , and the aim is to find successively better approximations to these. The zeroth-order approximation is simply and , which is just another way of saying that the perturbation is small.
Nomenclature for the perturbing Hamiltonian varies. , and are all common. It usually is a perturbing potential but we won’t assume so here, so we won’t use the first. The second and third differ in that the third has explicitly identified a small, dimensionless parameter (eg in EM), so that the residual isn’t itself small. With the last choice, our expressions for the eigenstates and energies of the full Hamiltonian will be explicitly power series in , so etc. With the second choice the small factor is hidden in , and is implicit in the expansion which then reads . In this case one has to remember that anything with a superscript (1) is first order in this implicit small factor, or more generally the superscript denotes something which is th order. For the derivation of the equations we will retain an explicit , but thereafter we will set it equal to one to revert to the other formulation. We will take to be real so that is Hermitian.
We start with the master equation
Then we substitute in and and expand. Then since is a free parameter, we have to match terms on each side with the same powers of , to get
We have to solve these sequentially. The first we assume we have already done. The second will yield and . Once we know these, we can use the third equation to yield and , and so on.
In each case, to solve for the energy we take the inner product with (ie the same state) whereas for the wave function, we use (another state). We use, of course, and .
At first order we get
The second equation tells us the overlap of with all the other , but not with . This is obviously not constrained, because we can add any amount of and the equations will still be satisfied. However we need the state to continue to be normalised, and when we expand in powers of we find that is required to be imaginary. Since this is just like a phase rotation of the original state and we can ignore it. Hence
If the spectrum of is degenerate, there is a potential problem with this expression because the denominator can be infinite. In that case we have to diagonalise in the subspace of degenerate states exactly. This is called “degenerate perturbation theory”.
Then at second order
The expression for the second-order shift in the wave function can also be found but it is tedious. The main reason we wanted was to find anyway, and we’re not planning to find ! Note that though the expression for is generally applicable, those for and would need some modification if the Hamiltonian had continuum eigenstates as well as bound states (eg hydrogen atom). Provided the state is bound, that is just a matter of integrating rather than summing. This restriction to bound states is why Mandl calls chapter 7 “bound-state perturbation theory”. The perturbation of continuum states (eg scattering states) is usually dealt with separately.
Note that the equations above hold whether we have identified an explicit small parameter or not. So from now on we will set to one, and .
Connection to variational approach:
For the ground state (which is always non-degenerate)
is a variational upper
bound on the exact energy ,
since it is obtained by using the unperturbed ground state as a trial wavefunction
for the full Hamiltonian. It follows that the sum of all higher corrections
must be negative. We
can see indeed that
will always be negative, since for every term in the sum the numerator is positive and the
denominator negative.
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